Problem 17.41 Enhanced- with Solution 29 of 33> Constants Find the magnitude of
ID: 1879159 • Letter: P
Question
Problem 17.41 Enhanced- with Solution 29 of 33> Constants Find the magnitude of the electric field at the origin. In a rectangular coordinate system, a positive point charge q = 4.00 nC is placed at the point 0.1 50m . y 0, and an identical point charge 1 is placed at x-:-0. 150m . y 0. Find the x and y çomponents and the magnitude and direction of the electric field at the following points. You may want to review (Pages 539-543) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electric field of an electric dipole. Submit Request AnswerExplanation / Answer
electric field at origin due to charge placed at x=0.15m,y=0 is 9*109*4*10-9/0.152 = 1600 (towards negative x direction)
electric field at origin due to charge placed at x=-0.15m,y=0 is 9*109*4*10-9/0.152 = 1600 (towards positive x direction)
net electric field at origin = 1600-1600=0
therefore, at origin,net electric field is 0