An object moves with constant acceleration 3.50 m/s2 and over a time interval re

Question

An object moves with constant acceleration 3.50 m/s2 and over a time interval reaches a final velocity of 10.2 m/s.
(a) If its initial velocity is 5.1 m/s, what is its displacement during the time interval?
1 m

(b) What is the distance it travels during this interval?
2 m

(c) If its initial velocity is -5.1m/s, what is its displacement during the time interval?
3 m

(d) What is the total distance it travels during the interval in part (c)?
4 m

Explanation / Answer

a) a=3.95 m/s2 v=final velocity of 10.2 m/s v^2=u^2+2as=>(10.2)^2=(5.1)^2+2(3.95)s where s is your displacement b.. distance is also same c...f its initial velocity is ?5.1 m/s, what is its displacement during the time interval same as a

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