An object moves with constant acceleration 3.50 m/s2 and over a time interval re

Question

An object moves with constant acceleration 3.50 m/s2 and over a time interval reaches a final velocity of 13.4 m/s.
(a) If its initial velocity is 6.7 m/s, what is its displacement during the time interval?
________m

(b) What is the distance it travels during this interval?
________m

(c) If its initial velocity is -6.7 m/s, what is its displacement during the time interval?
________m

(d) What is the total distance it travels during the interval in part (c)?
________m

I tried reviewing another question that was asked, just with different numbers but am not getting the correct answer. Please show steps and maybe it will become more clear. Thanks!

Explanation / Answer

a) v2 - u2 = 2as

13.42 - 6.72 = 2 x 3.50 x s

s = 134.67/7 = 19.24 m

b) distance will be also 19.24 m

c)

13.42 - (-6.7)2 = 2 x 3.50 x s

s = 19.24m

d) distance will be more . as now elocity is in opposite direction so first it will becone zero and then comes to final velocity.

0 - (-6.7)2 = 2 x 3.50 x d1

d1 = 6.41 m

13.42 - 02 = 2 x 3.50 x d2

d2 = 25.65 m

total distane = d1 + d2 = 6.41 + 25.65 = 32.06 m

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