Part A) The surface charge density on an infinite charged plane is - 1.60 ×106C/

Question

Part A) The surface charge density on an infinite charged plane is - 1.60 ×106C/m2. A proton is shot straight away from the plane at 1.60 ×106m/s. How far does the proton travel before reaching its turning point?

Part B) The electric field 5.80 cm from a very long charged wire is (2200 N/C , toward the wire). What is the charge (in nC) on a 1.00-cm-long segment of the wire?

Part C) Two 2.0-cm-diameter insulating spheres have a 5.80 cm space between them. One sphere is charged to + 87.0 nC , the other to - 78.0 nC. What is the electric field strength at the midpoint between the two spheres?

Explanation / Answer

part A )

charge density , p = -1.6 *10^-6 C/m^2

electric field , E = p/(2 * epsilon)

E = 1.6 *10^-6/(2 * 8.854 *10^-12)

E = 9.04 *10^4 N/C

let the acceleration is a

e * E = m * a

1.602 *10^-19 * 9.04 *10^4 = 1.67 *10^-27 * a

a = 8.66 *10^12 m/s^2

let the distance is d

d = (u^2)/(2 * a)

d = (1.6 *10^6)^2/(2 * 8.66 *10^12 )

d = 0.148 m

the proton will travel 0.148 m before turning

b)

eletric field = 2 *k * lamda/d

2200 = 2 * 9*10^9 * lamda/.058

lamda = 7.09 *10^-9 C/m

lamda = 7.09 *10^-11 C/cm

the charge on 1 cm sagment is 7.09 *10^-11 C

part C)

distance of midpoint, d = 5.8/2 cm

d = 2.9 cm

electric field = E1 + E2

electric field = 9*10^9 * 10^-9 * (87 + 78)/.029^2

electric field = 1.766 *10^6 N/C

the electric field at the midpoint is 1.766 *10^6 N/C

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