In the circuit shown in (Figure 1) , the potential difference across a b is 27.5

ID: 2001809 • Letter: I

Question

In the circuit shown in (Figure 1) , the potential difference across ab is 27.5V.

Part A

Calculate the charge on the 3.00 ?F capacitor.

Express your answer in microcoulombs to three significant figures.

Part B

Calculate the charge on the 5.00 ?F capacitor.

Express your answer in microcoulombs to three significant figures.

Part C

Calculate the charge on the 6.00 ?F capacitor.

Express your answer in microcoulombs to three significant figures.

Part D

Calculate the potential difference across the 3.00 ?F capacitor.

Express your answer in volts to three significant figures.

Part E

Calculate the potential difference across the 5.00 ?F capacitor.

Express your answer in volts to three significant figures.

Part F

Calculate the potential difference across the 6.00 ?F capacitor.

Express your answer in volts to three significant figures.

3uF and 5uF are paralllel.

so equivalent of these two will be = 3 + 5 = 8uF

now 8uF and 6uF are in series.

so 1/Ceq = 1/6 + 1/8

Ceq= 3.43 uF

PD across 6uF = 8 x 27.5 / (8 + 6) = 15.71 V

PD across 8uF = PD across 3uF = PD across 5uF = 11.79 V

A) charge on 3uF = CV = 3 uF x 11.79 V = 35.37 uC

B) charge on 5uF = 5 x 11.79 = 58.95 uC

C) charge on 6uC =6 x 15.71 = 94.29 uC

D) PD across 3uF = 11.79 V

E) PD across 5uF = 11.79 V

F) PD across 6uF = 15.71 V