Constants Part A Singly ionized (one electron removed) atoms are accelerated and

Question

Constants Part A Singly ionized (one electron removed) atoms are accelerated and then passed through a velocity selector consisting of perpendicular electric and magnetic fields. The electric field is 160 V/m and the magnetic field is 3.18x102T. The ions next enter a uniform magnetic field of magnitude 1.75x10-2 T that is oriented perpendicular to their velocity How fast are the ions moving when they emerge from the velocity selector? m/s Submit Request Answer Part B If the radius of the path of the ions in the second magnetic field is 17.0 cm, what is their mass? Submit Request Answer

Explanation / Answer

Part A

when ions pass through velocity selector. using force balance

Fe = Fm

q*E = q*v*B

v = E/B

v = 160/(3.18*10^-2)

v = 5031.45 m/sec

Part B

when ions enter in next magnetic field, now again using force balacne

Fc = Fm

m*v^2/r = q*v*B

m = q*B*r/v

r = 17 cm = 17*10^-2 m

Using known values:

m = 1.6*10^-19*1.75*10^-2*17*10^-2/5031.45

m = 9.46*10^-26 kg

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