Constants Part A Singly ionized (one electron removed) atoms are accelerated and

Question

Constants Part A Singly ionized (one electron removed) atoms are accelerated and then passed through a velocity selector consisting of perpendicular electric and magnetic fields. The electric field is 160 V/m and the magnetic field is 3.12x10 2 T. The ions next enter a uniform magnetic field of magnitude .74x102 T that is oriented perpendicular to their velocity. How fast are the ions moving when they emerge from the velocity selector? m/s Submit Request Answer Part B If the radius of the path of the ions in the second magnetic field is 17.0 cm, what is their mass? kg Submit Request Answer

Explanation / Answer

part A)

let the velocity of the ions is v

for the velocity selector

E = v * B

v = 160/(3.12 * 10^-2)

v = 5128 m/s

the speed is 5128 m/s

b)

let the mass ism

r = m* v/(B * q)

0.17 = m * 5128/(1.74 *10^-2 * 1.6 *10^-19)

solving for m

m = 9.23 *10^-26 Kg

the mass of the ions is 9.23 *10^-26 Kg

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