Remember that when dealing with collisions in 2-dimensions, momentum is conserve
ID: 2091204 • Letter: R
Question
Remember that when dealing with collisions in 2-dimensions, momentum is conserved in each dimension. Two pucks are sliding on a frictionless tabletop. Block A (mass 3.20 kg) is moving to the East (+x direction) at 2.50 m/s. Block B (mass 3.84 kg) is moving to the North (+y direction) at 3.00 m/s. Assume the system to be both Block A and Block B. (Note: It could be useful to make a drawing of the situation.) 1)What is the x-component of the total momentum of the system before the collision? 2)What is the y-component of the total momentum of the system before the collision? 3)What is the x-component of the total momentum of the system after the collision? 4)What is the y-component of the total momentum of the system after the collision?Explanation / Answer
1)
x component of total momentum before collision
=3.20 * 2.50
= 8 kgm/s
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2)
y-component of the total momentum of the system before the collision
= 3.84 * 3
= 11.52 kgm/s
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3)
As momentum is conserved in collision,
x-component of the total momentum of the system after the collision
=8 kgm/s
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4)
As momentum is conserved in collision,
y-component of the total momentum of the system after the collision
= 11.52 kgm/s