In the figure below, m 1 = 9.5 kg and m 2 = 4.5 kg. The coefficient of static fr

Question

In the figure below, m1 = 9.5 kg and m2 = 4.5 kg. The coefficient of static friction between m1 and the horizontal surface is 0.50, and the coefficient of kinetic friction is 0.30.

In the figure below, m1 = 9.5 kg and m2 = 4.5 kg. The coefficient of static friction between m1 and the horizontal surface is 0.50, and the coefficient of kinetic friction is 0.30. If the system is released from rest, what will its acceleration be? If the system is set in motion with m2 moving downward, what will be the acceleration of the system?

Explanation / Answer

a) max. value of Tension can be = 4.5g

maxc. vbalue of static friction = 0.50 x 9.5g = 4.75 g

friction > T

so blocks will not move

a = 0

b) set in motion , so kinetic friction wil act.

T - 0.30 x 9.5g = 9.5a

4.5g - T = 4.5a

add them

4.5g - 0.30x9.5g = (9.5+4.5)a

a = 1.16 m/s2

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