For the first nutcracker, two applied forces of magnitude F were required to cra

Question

For the first nutcracker, two applied forces of magnitude F were required to crack the nut, whereas for the second, only one applied force of magnitude F was required. How would you explain this difference? For the first nutcracker, two applied forces of magnitude were required to crack the nut, whereas for the second, only one applied force of magnitude was required. How would you explain this difference? In the second case the nutcracker handle is effectively longer and generates twice the torque of that in the first case. There is an additional force of magnitude F_n applied to the nut by the fixed jaw in the second case. This jaw is held fixed by external forces (such as the forces due to the frame). The net torque on the nutcracker in the second case is non-zero.

Explanation / Answer

CORRECT ANSWER is

This jaw is held fixed by external forces (such as the forces due to the frame).

Explanation

In the first case the jaw is not fixed so to generate required force (F) two equal and opposite force is applied while in second case the jaw is held fixed so only single force (F) is required.

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