Mass m1 = 11.3 kg is on a horizontal surface. Mass m2 = 8.03 kg hangs freely on

Question

Mass m1 = 11.3 kg is on a horizontal surface. Mass m2 = 8.03 kg hangs freely on a rope which is attached to the first mass. The coefficient of static friction between m1 and the horizontal surface is mu s = 0.624, while the coefficient of kinetic friction is mu k = 0.183. If the system is set in motion with m1 moving to the right, then what will be the magnitude of the system's acceleration? Consider the pulley to be massless and frictionless. Tries 3/12 Previous Tries If the system is set in motion with m1 moving to the left, then what will be the magnitude of the system's acceleration? Tries 2/12 Previous Tries

Explanation / Answer

a) m2g - T = m2a T - mu*m1*g = m1 a add both (m2- u*m1)*g = (m2+m1)*a a = (8.03 - 0.183*11.3)*9.8 /(11.3+8.03) = 3.022 m/s^2 b)- 3.022 m/s^2

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