QUESTION 1: Problem 6.19) Figure P6.19 shows a circuit with a resistor, an induc
ID: 2267553 • Letter: Q
Question
QUESTION 1: Problem 6.19) Figure P6.19 shows a circuit with a resistor, an inductor, and a capacitor in parallel. Kirchhoft s rules can be used to express the impedance of the system as where Z= impedance (), and co is the angular frequency. Find the co that results in an impedance of 100 using the zero function with initial guesses of l and 1000 for the following parameters: R-225 , C-0.6x10-6F, and L-0.5 H. (a) Using the Newton-Raphson method (x-1) (b) Using the secant method (x1-1 andx -3). (c) *Using the modified secant method (-1.0. = 0.01 ir practice purpose) L -C FIGURE P6.19Explanation / Answer
%|R=L=C=1|:
R = 225; L = 1; C = 0.6× 10 ^ -6;
G = tf([1/(R*C) 0],[1 1/(R*C) 1/(L*C)])bode(G), grid
R1 = 225; G1 = tf([1/(R1*C) 0],[1 1/(R1*C) 1/(L*C)]);
R2 = 20; G2 = tf([1/(R2*C) 0],[1 1/(R2*C) 1/(L*C)]);
bode(G,'b',G1,'r',G2,'g'), grid
legend('R = 1','R = 5','R = 20')
t = 0:0.05:250;
opt = timeoptions;
opt.Title.FontWeight = 'Bold';
subplot(311), lsim(G2,sin(t),t,opt), title('w = 1')
subplot(312), lsim(G2,sin(0.9*t),t,opt), title('w = 0.9')
subplot(313), lsim(G2,sin(1.1*t),t,opt), title('w = 1.1')
damp(pole(G2))
rlc_gui