Please Explain, thank you. How would the equivalent resistance of a circuit chan

Question

Please Explain, thank you.

How would the equivalent resistance of a circuit change if another resistance, R, is Connected in series with the circuit? in parallel with the circuit? [Hint: Recall the relation between resistivity and resistance and try thinking about a series-connection as "adding more length", and about a parallel-connection as "adding more area] A home appliance experiences a voltage drop of 4.0 V across it while a current of 4 Amperes flows through it. How much power does it dissipate? A battery is rated that it provides 64 Watts of power at 20 V when fully charged. How much current can it deliver?

Explanation / Answer

1.

a)

Let Ro be the initial resistance

a)

When Resistor R is connected in series ,then equivalent resistance

Req =Ro+R

b)

When Resistor R is connected in parallel then equivalent resistance

1/Req =1/R +1/Ro

=>Req =R*Ro/(R+Ro)

2.

Power =Voltage *Current

P=VI =4*4

P=16 Watts

3.

P=VI

=>I=P/V =64/20

I=3.2 Amperes

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