In the figure below ( Figure 1 ) , each capacitance C 1 is 6.90 ? F and each cap
ID: 2276531 • Letter: I
Question
In the figure below (Figure 1) , each capacitance C1 is 6.90?F and each capacitance C2 is 4.60?F .
a) Compute the equivalent capacitance of the network between points
a and b.
C1 capacitor nearest a and b when
c)Compute the charge on
C2 capacitor nearest a and b when Vab=420V
Please and thank you :)
In the figure below (Figure 1) , each capacitance C1 is 6.90?F and each capacitance C2 is 4.60 Compute the equivalent capacitance of the network between points a and Compute the charge on capacitor nearest a and b when Compute the charge on capacitor nearest a and b whenExplanation / Answer
C1 = 6.9 ?F
C2 = 4.6 ?F
a) Ccd = C1/3 + C2 = 2.3 + 4.6 =6.9 ?F =C1
this follow again
finally
Ceq =Cab =C1/3 = 2.3 ?F
b) Vab= 420V
Q = Ceq*Vab = 2.3*10^-6*420 = 966?C
Qc1 =Q =966 ?C
Vc2 = Q/C1 = Vab/3 = 140V
Qc2 =C2*Vc2 = 4.6*10^-6*140 =644 ?C