Please Help... Lost at this point and not sure why I am getting this wrong!!! Wi
ID: 2301018 • Letter: P
Question
Please Help... Lost at this point and not sure why I am getting this wrong!!! Will rate!
The object in the figure below is midway between the lens and the mirror, which are separated by a distance d = 24.9 cm. The magnitude of the mirror's radius of curvature is 20.1 cm, and the lens has a focal length of -17.4 cm. Considering only the light that leaves the object and travels first toward the mirror, locate the final image formed by this system. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four¬digit accuracy to minimize roundoff error, cm to the right of the lens Is the image real or virtual? Is it upright or inverted? What is the overall magnification of the image? Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four¬digit accuracy to minimize roundoff error.Explanation / Answer
1/f1 = 1/v1 + 1/u1
-1/10.05 = 1/v1 - 1/12.45
1/v1 = -1/10.05 + 1/12.45
v1 = -52.13 cm
1/f2 = 1/v2 - 1/u2
-1/17.4 = 1/v2 + 1/39.68
1/v2 = -1/17.4 - 1/39.68
v2 = 12.1 cm
FINAL IMAGE WILL BE FORMED 12.1 CM TO THE RIGHT OF THE LENS
IMAGE IS VIRUAL AND INVERTED
m = v2/u2
= -12.1 / 39.68
= -0.304