Problem 17.26 flanking an essential Hox7 Loss-of-function alleles of Hoxa7 and H
ID: 266958 • Letter: P
Question
Problem 17.26 flanking an essential Hox7 Loss-of-function alleles of Hoxa7 and Hoxb7 could be created by performing gene knockouts for each gene. The gene knockout would be performed by creating a transgene that contains DNA corresponding to the internal region of an essential Hox7 exon with a negative selectable marker in the place of an exon. A negative selectable marker would be included outside the DNA flanking an essential Hox7 exon. Injection of this construct into mouse germ line cells and selection for the posltive selectable marker and against the negatlve selectable marker would yield clones containing the knockout of at least one Hox7 gene . These positive cells would then be used to generate mice that carry the knockout construct in their germ line cells exon corresponding to the internal region of an essential Hoxi exon positive negative egg sperm ES germ line at least one Hox7 gene both Hox7 genes Submit Previous Answers Request Answer Incorrect, One attempt remaining; Try Again You filled in 4 of 10 blanks incorrectlyExplanation / Answer
2.A positive selctable marker in place of exon.
3.A negative selectable marker would be included outside the DNA, flanking an essential hox7 exon.
4.Injection of this construct into mouse ES cells and selection for the negative selectable marker against the positive selectable marker would yield clone..
5.These ES cells will then be used to gnenrate mice that carry knockout construcy in their germ line cells.