Please Help A solid above the cone z = Squareroot x^2 + y^2 and below the sphere

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A solid above the cone z = Squareroot x^2 + y^2 and below the sphere x^2 + y^2 + z^2 = 5z. Write a description of the solid in terms of inequalities involving spherical coordinates. 0 lessthanorequalto rho lessthanorequalto cos Phi, 0 lessthanorequalto theta lessthanorequalto 2 pi, 0 lessthanorequalto Phi lessthanorequalto pi/4 0 lessthanorequalto rho lessthanorequalto 5cos Phi, 0 lessthanorequalto theta lessthanorequalto pi, 0 lessthanorequalto Phi lessthanorequalto pi/4 0 lessthanorequalto rho lessthanorequalto 5cos Phi, 0 lessthanorequalto theta lessthanorequalto pi, 0 lessthanorequalto Phi lessthanorequalto pi/4 0 lessthanorequalto rho lessthanorequalto 5cos Phi, 0 lessthanorequalto theta lessthanorequalto 2 pi, -pi/4 lessthanorequalto Phi lessthanorequalto pi/4 0 lessthanorequalto rho v 5cos Phi, 0 lessthanorequalto theta lessthanorequalto 2pi, 0 lessthanorequalto Phi lessthanorequalto pi

Explanation / Answer

in spherical coordinates

x=sincos,y=sinsin,z=cos

x2+y2+z2=2

z=(x2+y2) ,x2+y2+z2=5z

cos=(2sin2) ,2=5cos

cos=sin ,(-5cos)=0

=/4 ,=0,=5cos

0<=<=5cos,0<=<=2,0<=<=/4

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