College X ?? www.saplinglearning.com/ibiscms/mod/ibis/view.php?id-5707901 pling

Question

College X ?? www.saplinglearning.com/ibiscms/mod/ibis/view.php?id-5707901 pling Learning Consider this reaction data If you were going to graphically determine the activation energ this reaction, what points would you plot? Aproducts Number point 1: To avoid ro errors, use a three signific figures in all 325 0.387 875 0.792 Number point 2: Determine the rise, run, and slope of the line formed by these points nse run slope Number 0.7161 -0.0019 What is the activation energy of this reaction 3078.3 J/ mol

Explanation / Answer

The graph will be between ln(K) v/s 1/T

Point1: x = 1/325 =0.0030769 , y = ln(0.387) = -0.94933

Point2: x = 1/875 =0.0011428, y = ln(0.792) = -0.23319

rise = y2 - y1 = -0.23319 + 0.94933 = 0.71614

run = x2 - x1 = 0.0011428 - 0.0030769 = -0.001934

Slope = rise/run = 0.71614/(-0.001934) = -370.289 J/K.mol

Delta H = -Slope * R = 370.289 * 8.314 = 3078.58 J/mol

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