Instead of considering a data value to be an outlier if it is \"very far away fr
ID: 3132757 • Letter: I
Question
Instead of considering a data value to be an outlier if it is "very far away from almost all of the other data values," consider an outlier to be a value that is above Q_3 by an amount greater than 1.5 times IQR or below Q_1 by an amount greater than 1.5 times IQR. Use the data set given below to find (a) the 5-number summary, (b) the interquartile range (IQR), and (c) any outliers. 1 2 3 4 5 10 13 14 14 15 21 31 55 The 5-number summary is. (Type exact answers. Use ascending order.) The interquartile range is. The outliers are. (Use a comma to separate answers as needed.)Explanation / Answer
a. For five number summary, check whether the data are in ascending order. It is in ascending order, therfore, th eminimum number is 1 and Maximum number is 55.
The centre is median, the middle most value, 13.
First quartile, Q1 is (3+4)/2=3.5 [Average of middle most number sof 1 st half] and third quartile, Q3 is (15+21)/2=18
5 number summary: 1, 3.5, 13, 18, 55
b. Interquartile range, Q3-Q1= 18-3.5=14.5
c. Outliers 1, 2, 3, 4