Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

In (Figure 1), a beam of protons moves through a uniform magnetic field with mag

ID: 3162283 • Letter: I

Question

In (Figure 1), a beam of protons moves through a uniform magnetic field with magnitude 2.0 T, directed re along the positive z axis. The protons have a velocity of magnitude 3.0 times 10^5 m/s in the z-plane at an angle of 30 degree to the positive z axis. Find the force on a proton. The charge of the proton is q +1.6 times 10^-19 C. force acts in the -y direction. SOLVE To find the magnitude of the force, use the magnetic force equation: REFLECT We could also obtain this result by finding B_1 and applying F = q vB. However, since we were given the angle the equation we used is more convenient. To check for consistency units, of we recall that 1T = 1 N/(A middot m) Part A Practice Problem: An electron beam moves through a uniform magnetic field with magnitude 4, 3 T, directed in the -z direction. The electrons have a velocity of 3.0 times 10 m/s in the y z plane at an angle of 34 from the z axis toward the +y axis. Find the force on an electron.

Explanation / Answer

We wil solve it byy normally using the formula F=qvBsintheta

here q=+1.6*10^-19 C v=3*10^5 m/s and B=2 T and theta= 30 degree

using the formula F=1.6*10^-19 *3*10^5*2*sin30 = 4.8*10^-14 N