If you could include how you got your answers for parts (c) and (d), it would be

Question

If you could include how you got your answers for parts (c) and (d), it would be greatly appreciated. Thanks!

5TA7307 HW 10-ANCA: x cowww.webassi t/Assignment-Responses'submit?dep= 1 /523 1 1 y pp Publir Service Crodit amazonsmilcnlser Dashbcard C Ramich Colprado St Introduction ntAstronamy BcakanMastering Chem andW WAssign Stat 30Imported From IF besily and beinu uver weight caused by excess ve duipuse ussues ur budy al. Viscer a su"uunL 11 "ternal uruan 's deal dssuud e with heat uisease d eeles. Subcu arieus a uun us bt ow l te skin DI en in te buttocks and thighs), is not. A study examined the impact of exercise type on visceral and subcutaneous fat. Overweght. sedentary, but otherwise disease-free adults were randomly assiqned to 3 exercise regimens for eight months aerobic training, resistance training, aerobic plus resistance treining. All exercise sessions were supervised to ensure correct complebon. he subjects' body fat amount was assessed with computed tomography imaging in cm at the baginning and end of the experimant. The study report contains the following information about the visccral fat reduction (in cm) ochizved by the subjccts in cach group (note that the roduction is indicatod as a positive valuc): Aerobic training Resistance training Aerobic plus resistance training 38 25.5 33 11 8.1 55 35 28.3 37 a) Do the standard deviations s the rule of thumb for safe use of ANOVA? Yes, the largest s mple standard deviation is lms th n twi1 rge the smallest 5 mple smndard deviation. No, the largest semple standard devietion is more than twice as large as the smallest sample standard deviation. (b)The report daes nat provide the distributions af subatanecus fat reductian. ANOVA is nonetheless safe far these data. Why? The sample sizes are smal The sample sizrs are larg. The standard deviation has Normality. The populations have the same standard devintion. (c) Calculate the overall mean responsex, the mean square for groups MSIr, and the mean square for eor MSE. (Round your answers to two decimal places.) x-2063 MSTr = MSF = (d) Find thr ANOVA F statitic and appta v (Raund your answer to two decimal places.) P-value: 0.001 P0.010 0.025P

Explanation / Answer

from above information:

grand mean =(38*25.5+41*8.1+35*28.3)/(38+41+35)=20.10

MSTr=4682.74

MSE =1872.42

c)F =MStr/MSE =2.50

d) p value :0.05<p <0.10

i ni Xi Si^2 ni*(Xi- grand mean)^2 (ni-1)*Si^2 aerobic 38 25.5 1089.000 1107.360 40293.000 resistance 41 8.1 3025.000 5905.726 121000.000 both 35 28.3 1369.000 2352.393 46546.000 grand mean 20.102 9365.480 207839.000 SSG SSE Source of variation SS df MS F P value treatment 9365.480 2 4682.740 2.501 0.0866 error 207839.000 111 1872.423 total 217204.480 113

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