Please answer the questions 24-28, thanks~!!! Refer to Exhibit 4, At 95% confide
ID: 3325647 • Letter: P
Question
Please answer the questions 24-28, thanks~!!!
Refer to Exhibit 4, At 95% confidence, the conclusion is the a. average salary of males is significantly greater than females b. average salary of males is significantly lower than females c. salaries of males and females are equal d. None of the above 24, Exhibit 5 The following information was obtained from matched samples Individual Method 1 Method 2 25. Refer to Exhibit S. The point estimate for the difference between the means of the two populations is b. 0 d. 2 Refer to Exhibit 5, The 95 a. -3.776 to 1.776 b. -2.776 to 2.776 c. -1.776 to 2.776 d. 0 to 3.776 Refer to Exhibit 5. The null hypothesis tested is He -0. The test statistic for the difference between the two population means is a. 2 b. 0 26. % confidence interval for the difference between the two population means is 27, 28, Refer to Exhibit 5.1 f the null hypothesis is tested at the 5% level, the null hypothesis a. should be rejected b. should not be rejected c. should be revised d. None of these alternatives is correct Exhibit 6 In the last presidential election, before the candidates started thetr major campaigns, the percentages of registered voters who favored the various candidates were as follows Percentages 34% 43% 23% Republicans Democrats Independents After the major campaigns began, a random sample of 400 voters showed that 172 favored the Republican candidate: 164 were in favor of the Democratic candidate; and 64 favored the Independent candidate. We are interested in determining whether the proportion of voters who favored the various candidates had changed. Use -01 Refer to Exhibit 6. Compute the test statistic a. 20.17 b. 18.42 c 4.605 d. None of the above 29.Explanation / Answer
25)
the last row indicates the average.
the answer is a) -1
26)
t-value is calculated by t-value (0.05 probability, 4 df)
answer is
a) -3.776 to 1.776
27)
test statistic = diff in means/ (sd of diff in means/ sqrt(n)) = -1/( 2.2361/sqrt(5) ) = -1
answer is c) -1
28)
p-value is t.dist.2t(1,df=4) i.e. 0.3739
since p-value is greater than 0.05 donot reject null hypothesis
the answer is
b) should not be rejected
M1 M2 DIFFERENCE 7 5 2 5 9 -4 6 8 -2 7 7 0 5 6 -1 6 7 -1