I need help with this question. The options are: reject, fail to reject , signif

Question

I need help with this question. The options are: reject, fail to reject , significant, not significant 0.154, 0.05, .10 40,80,20
The inverse t distribution was 1.984 From these 100 study participants, you found the mean blood glucose level for everyone before breakfast was 80 mg/dL and the mean blood glucose level for everyone after breakfast was 120 mg/dL. From the data that you have collected (which are not shown here), you successfully computed the sum of squares, which allows you to compute the variance, which then allows you to compute the estimated standard error, which finally allows you to compute the calculated t score (refer to your lecture slides for Testing Means to follow through these steps). That calculated t score you got was t = 2.466. What is the correct conclusion here? (select the correct answer for each missing spot) "As I compare my calculated t score here (t-2.466) to the critical t score (in previous question), I Choose... the null hypothesis. From my study of 100 participants, I conclude that blood glucose level before and after breakfast was Choose... From my data, that average difference was mg/dL." Choose ^ different, with p-value= .

Explanation / Answer

as test statistic is greater then critical value at 0.05 level

reject the null hypothesis ; from my study.....................after breakfast was significantly differnt with p value 0.0154

from my data that average differnce was 40 mg/dl

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