The Code should be in Prolog Segregate Define a predicate segregate/3 that takes
ID: 3598192 • Letter: T
Question
The Code should be in Prolog
Segregate
Define a predicate segregate/3 that takes a list of integers as an argument and generates two lists, the first containing containing the even numbers from the original list and the second sublist containing the odd numbers from the original list. Your predicate should have the signature segregate(List, Even, Odd). Examples: ?- segregate([8,7,6,5,4,3], Even, Odd). Even = [8,6,4] Odd = [7,5,3] ?- segregate([7,2,3,5,8], Even, Odd). Even = [2,8] Odd = [7,3,5] ?- segregate([-4,11,-7,9,0], Even, Odd). Even = [-4,0] Odd = [11,-7,9] ?- segregate([5,13,29], Even, Odd). Even = [] Odd = [5,13,29] ?- segregate([], Even, Odd). Even = [] Odd = []
Explanation / Answer
def segregate (list, even, odd) :
if len (list)<=0 :
return even, odd
for I in list :
if I % 2==0 :
even .append ( i )
return even, odd
even=[ ]
odd=[ ]
list= [1,2,3,4,5,6,7,8,9 ]
even, odd=segregate ( list, even, odd )
print (“even= “+str (even) )
print (“odd= “str (odd) )
even= [ 2, 4, 6, 8 ]
odd= [1, 3, 5, 7, 9]