Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Please do this in C++ using only for loops, while loops, and do while loops. No

ID: 3908587 • Letter: P

Question

Please do this in C++ using only for loops, while loops, and do while loops. No arrays.

Use for loop, while loop, and do while loops to generate a table of decimal numbers, as well as the binary, octal, and hexadecimal equivalents of the decimal numbers in the range 1-256 Note: See Appendix for number systems The program should print the results to the Console without using any string formats Design Details: The Main program should prompt the user for input. The output is shown in the sample output below Note: To generate the binary numbers your code should use a while loop to generate the binary numbers, a "for" loop to generate the octal numbers and a "do .. while" to generate the hexadecimal numbers Sample Output: Enter the low number: Enter the high number: 10 Decima ? Binary Octal Hexadecimal 1 10 100 101 110 10 1000 1001 1010 10 12 ***Resetting low and high Low10, High-15 Decimal Binary 10 12 13 14 15 1010 1011 1100 1101 1110 Octal hexadecimal 12 13 14 15 16 17 Press any key to continue .. .

Explanation / Answer

#include<iostream>
#include<math.h>
using namespace std;
int main()
{
   int i,j,high,low,dnum,rem,bnum,rem1,onum,k,l,hexnum,hnum,m,rem2;
   char ch;
  
   cout<<"Enter the lowest number : ";
   cin>>low;
   cout<<"Enter the hightest number : ";
   cin>>high;
  
   //finding binary number
   for(i=low;i<=high;i++)
   {
       dnum=i;
       j=0;
       bnum=0;
       while(dnum!=0)
       {
           rem=dnum%2;
           bnum+=rem*pow(10,j);
           j++;
           dnum=dnum/2;
          
       }
      
       //finding octal number
      >        l=0;
       for(k=i;k!=0;k=k/8)
       {
           rem1=k%8;
           onum+=rem1*pow(10,l);
           l++;
          
       }
      
       //finding hexadeciaml number
       hexnum=0;
       hnum=i;
       m=0;
       do
       {
           rem2=hnum%16;
           hexnum+=rem2*pow(10,m);
           m++;
           hnum=hnum/16;
       }
       while(hnum!=0);
      
       switch(hexnum)
       {
          
           case 10:
               ch='A';
               break;
           case 11:
               ch='B';
               break;
           case 12:
               ch='C';
               break;
           case 13:
               ch='D';
               break;
           case 14:
               ch='E';
               break;
           case 15:
               ch='F';
               break;

       }
      
       //printing the result
       if(hexnum<=9)
       {
           cout<<i<<" "<<bnum<<" "<<onum<<" "<<hexnum<<endl;
       }
       else
       {
           cout<<i<<" "<<bnum<<" "<<onum<<" "<<ch<<endl;
       }
   }
   return 0;
}