Mass of empty calorimeter (g) Mass of calorimeter and water (g) Mass of water (g

Question

Mass of empty calorimeter (g) Mass of calorimeter and water (g) Mass of water (g) Mass of empty test tube (g) Water temperature after the addition of hot lead. Mass of test tube and lead (g) Time Temp Mass of lead (g) Initial temperature of water Temperature of hot lead (degree C) Final temperature of water degree C) Change in temperature of water (degree C) Heat added to water (cal) Change in temperature of lead (degree C) Experimental specific heat (cal/g degree C) Specific heat from table (cal/8 degree C) Percent Error (%)

Explanation / Answer

heat added to water

Q = m c Delta T

m = mass of water = 49.72 gm

C= heat capacity = 1 cal/gm C

Delta T = change in temp of water = 61 C

Therefore Q = 49.72 * 1 *61 = 3032.92 cal

3032.92 = unknown mtl mass * heat cap of unknown mtl * Delta T of unknown mtl

3032.92 = 30* c * 57

Therefore C= 1.774 cal/gm C -----------Heat capacity of unknown mtl

Find unknown mtl from chart

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