Substance Densny ot air 789 N. 21 gas at STP 1. The table above gives the tsty o

Question

Substance Densny ot air 789 N. 21 gas at STP 1. The table above gives the tsty of con gas and air at STP. Explainthe assa motion ot lhe co does not need to be capped whie subining and that air in the task is being displaced as the con 2. Performing his same exporment, what would happen a larger amount of dry ce was used? Would this produce a large smaler, or have no ettect on the caoulated molar wolume of cor? Please explain latter obtaining the original mass of the nask stopper, n the midde at the expenmen and air a stopper win a smaller mass was used to obtain the new th a dry ice subimed What would happen to the calculated molar volume of CO? 4 One mole of gas occupies 320 Lat a temperature of 125 o ec and a pressure of 7000 torr Calculate the pressure in torr temperature is reduced o 50.0 °C and the the volume is reduced to 1.30 L

Explanation / Answer

Q1.

Density of CO2 = 1.977 g/L at STP

Clearly, the CO2 will remain LOWER, since it is heavier than the air

so no need to close the container; CO2 will remain in the bottom

Q2.

if more dry ice is used, then more CO2 will form as gas

The effect should be the same molar mass, if we account for the total pressure change

Q3.

If it has less mass, then it excertes less pressure, so the volume of the gas increases

The calcualted volume will increase, so the Molar volume increases ) incorrectly

Q4

Apply ideal gas law ratios

P1V1/T1 = P2V2/T2

700*3.2/(125+273) = P2*1.3/(50+273)

P2 = 700*3.2/(125+273) *(50+273)/1.3

P2 = 1398.3764 torr

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