Consider the reaction: CuCO_3-Cu(OH_)_2(s) rightarrow 2 Coo(s) + H_2O(g) + CO_2(

Question

Consider the reaction: CuCO_3-Cu(OH_)_2(s) rightarrow 2 Coo(s) + H_2O(g) + CO_2(g) 1 What is the molar mass of CuCO_2-Cu(OH)_2? 2. What total mass of H_2O and CO_2 will be produced when 1.000 mole of CuCO_3-Cu(OH)_2 is decomposed? 3. A 2.3995 g mixture containing malachite and an inert ingredient lost 0.2997 g of H-2O and CO_2 when decomposed by heating to constant mass. a. How many moles of malachite in the mixture produced this mass of CO_2 and H_2O? b. How many grams of malachite were present in the mixture?

Explanation / Answer

Ans 1.

To find the molar mass of the compound , one needs to sum up the individual atomic masses of the atoms present in the compound .

So the molar mass of CuCO3.Cu(OH)2 will be

= (2x 63.546) + 12.008 + (5 x 16) + (2x1.008)

=221.116g/mol

Ans 2. 1 mole of the compound decomposes to ghive 1 mole of CO2 and 1 mole of H2O

The molar mass of CO2 = 44 g/ mol

The molar mass of H2O = 18.016 g/mol

So the mass of CO2 and H2O produced will be 44 grams and 18.016 grams respectively.

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