Can someone explain in detail all of the steps to do thisproblem? A 2.14-L sampl

Question

Can someone explain in detail all of the steps to do thisproblem? A 2.14-L sample of hydrogen chloride (HCl) gas at 2.61 atm and28oC is completely dissolved in 668 mL of water to formhydrochloric acid solution. Calculate the molarity of the acidsolution. Assume no change in volume. Answer: 0.338 M Can someone explain in detail all of the steps to do thisproblem? A 2.14-L sample of hydrogen chloride (HCl) gas at 2.61 atm and28oC is completely dissolved in 668 mL of water to formhydrochloric acid solution. Calculate the molarity of the acidsolution. Assume no change in volume. Answer: 0.338 M

Explanation / Answer

PV=nRT
(2.61 atm)(2.14 L HCl) = n(0.0821L-atm/K-mol)(298 K)

n = 0.228 M HCl

make sure you convert the information given toappropriate units where necessary

Now, you have a molar value for HCl and a volumeof water, you should know what to do now:

M = (moles)/(volume [L])

M = (0.228 M HCl)/(0.668 L water) = 0.341 M

this doesn't match the answer you gave, but I'vetried this problem several times making adjustments and find thisanswer every time

I tried my best.

Now, you have a molar value for HCl and a volumeof water, you should know what to do now:

M = (moles)/(volume [L])

M = (0.228 M HCl)/(0.668 L water) = 0.341 M

this doesn't match the answer you gave, but I'vetried this problem several times making adjustments and find thisanswer every time

I tried my best.
M = (moles)/(volume [L])

M = (0.228 M HCl)/(0.668 L water) = 0.341 M

this doesn't match the answer you gave, but I'vetried this problem several times making adjustments and find thisanswer every time

I tried my best.

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