Consider the reaction: H 2 (gas) + O 2 (gas) =H 2 O 2 (gas) (a) Pure H 2 O 2 (ga

Question

Consider the reaction:
H2 (gas) + O2 (gas) =H2O2 (gas)
(a) Pure H2O2 (gas) is introduced into aconstant (1.514 atm) pressure reactor at 249.5 oC. Asthe reaction proceeds towards equilibrium, the temperature andpressure are held constant, but the equilibrium reactor volume isfound to be 67.1% larger than the initial volume. What is theequilibrium constant, Kp, for the reaction at thistemperature?
(b) 11.93 atmospheres of H2O2 (gas) areintroduced into a constant volume reactor at 154.9 oC.The total pressure in the reactor at equilibrium is found to be14.14 atmospheres at equilibrium. What is the equilibrium constantKp for the reaction at this temperature?

Explanation / Answer

I know the answer is suppose to be 0.8065 for (a) and 1.9901 for (b), but I don't know how to get those numbers

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---