I have these equation below 2O 3 -> 3O 2 H= -427kj O 2 ->2O H= 495kj NO + O 3 ->

Question

I have these equation below
2O3 -> 3O2 H= -427kj O2 ->2O H= 495kj
NO + O3 -> NO2 + O2 H=-199kj


I need to fine H for this equation below :
NO + O2 -> NO2  H=? I could manage everything except I wasn't really surewhat I was supposed to do with 2O. Please give me detailed answer. Thanks.
I have these equation below
2O3 -> 3O2 H= -427kj O2 ->2O H= 495kj
NO + O3 -> NO2 + O2 H=-199kj


I need to fine H for this equation below :
NO + O2 -> NO2  H=? I could manage everything except I wasn't really surewhat I was supposed to do with 2O. Please give me detailed answer. Thanks.

Explanation / Answer

I suppose the equation you require is this:        2 NO + O2 -----> 2 NO2 It needs to be balanced. . We can get this equation, by mulitplying eq 3 by 2 and adding tothe inverse of eq. 1 2 NO + 2 O3 ------> 2 NO2 + 2 O2   H= - 398 kJ     3 O2 -------> 2 O3                      H = 427 kJ ________________________________ 2 NO + O2 ------> 2NO2        H = + 29 kJ

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