Can someone please help me to do the algebra for equation A and W. I want to fin

Question

Can someone please help me to do the algebra for equation A and W. I want to fine m4,m5 and m1. Can you explain the algebra thank you so much In a two stage process, acetic acid (A) is extracted from water (W) into hexanol (H) in a liquid- liquid extraction vessel and the extract is subsequently separated by distillation. Assume that water is completely insoluble n hexanol A moture of 18 wt% acetic acid and the balance water is fed to a liquid-liquid extraction vessel. Pure hexanol is fed to the column to extract the acetic acid. The water-rich stream leaving the vessel is 99.5 wt% water and the balance acetic acid. The hexanol-rich extract from the vessel is fed to a distillation column. The composition of the distillate is 96 wt% acetic acid and the balance hexanol. The bottoms stream contains 972 wt% hexanol and recovers 95% of the hexanol fed to the liquidiquid extract on vessel Calculate the percentage of acetic acid in the process feed thatis recovered in the distilate stream 0 n, 0132 H 0-945 W 0.00 A 2 - 2 00F same i2 ri : (0-18) (o)100) 0 35-04 0.04 0-04 ms125.89

Explanation / Answer

When there is more than 1 unknown in a equation, the equations are expressed in terms of a single unknown. In this case m5 is calculated from Equation H and m1 can be expressed in terms of m4.

Equation A is 0.18m1+100=0.005m4+0.96m5+ 0.028(97.7)

Equation W is 0.82m1=0.995m4

m1= (0.995/0.82) m4

m1= 1.213 m4

Equation H is (1*100)=0.04m5+(0.972*97.7)

100=0.04m5+94.9644

0.04m5= 5.0356

m5= 125.89

Substitute the value of m5 and m1 in Equation A

0.18m1+100=0.005m4+0.96m5+ 0.028(97.7)

0.18(1.213 m4)+100=0.005m4+0.96(125.89)+ 0.028(97.7)

0.218m4-0.005m4= 120.85+2.735-100

0.213m4= 23.585

m4= 110.72

Substitute the value of m4 in Equation W

m1= 1.213 m4=1.213*110.72

m1=134.30

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---