Answer questions 10 and 11 from information 3 and 4 questions. 3. Using the answ
ID: 714227 • Letter: A
Question
Answer questions 10 and 11 from information 3 and 4 questions.
3. Using the answer from number 2 and the Ideal Gas Law equation, calculate the Pressure in the can (in mb) when the temperature is 20oC. (Hint 20o C = 293K) Show your work. (2)
T = c = 293k
P = rt/v = 8.314 x 293 / 1.12676
= 2162 Pa
= 21.62 mb
4. Using the answer from number 2, and the Ideal Gas Law equation, calculate the pressure in the can (in mb) when the temperature is 100oC (373 K). Show your work. (2)
P = rt/v
= 8.314 x 373 / 1.12676
= 2572.3 Pa
= 25.73 mb
10. How does the pressure you calculated compare to the average atmospheric pressure (1013.25 mb)? Use this information to explain what happened in the question (3)
11. How is what happened questions 3 and 4 related to the relationship between temperature and pressure in the troposphere shown in Figure 8 (3)
Explanation / Answer
Question 10:
Average atmospheric pressure (1013.25mb) is generally calculated in the temperature range of 23-25° C. In question 3 above the pressure at 20°C is 21.62 mb, which shiws that with decrease in temprature the pressure inside can also decrease.
Also the pressure inside can is not much effected by the atmospheric pressure and has it's own pressure.
Question 11:
From question 3 and 4 we see that the pressure increases with increase in temperature. Therefore we can conclude that pressure is directly proportional to temprature.
Also from ideal gas equation
PV=nRT, at constant volume P and T are directly proportional.