Show Work please 34 mls of 0.10 M HCl Solution The answer is: 34 mls of 0.10 M a
ID: 785192 • Letter: S
Question
Show Work please
34 mls of 0.10 M HCl
Explanation / Answer
The answer is: 34 mls of 0.10 M acetic acid
Moles of sodium acetate = 64/1000 x 0.10 = 0.0064 mol
Moles of acetic acid = 34/1000 x 0.10 = 0.0034 mol
Henderson-Hasselbalch equation:
pH = pKa + log([sodium acetate]/[acetic acid])
= pKa + log(moles of sodium acetate/moles of acetic acid)
= 4.76 + log(0.0064/0.0034)
= 5.03 (or approximately pH 5)