Problem 14.65 The rate of the reaction C H 3 C O O C 2 H 5 ( a q ) + O H ? ( a q

Question

Problem 14.65 The rate of the reaction
CH3COOC2H5(aq)+OH?(aq)?CH3COO?(aq)+C2H5OH(aq)
was measured at several temperatures, and the following data were collected:
Temperature (?C) k(M?1s?1) 15 0.0521 25 0.101 35 0.184 45 0.332
Part A Using these data, graph lnk versus 1/T.

Part B Calculate the value of Ea by using your graph.






Problem 14.65 The rate of the reaction
CH3COOC2H5(aq)+OH?(aq)?CH3COO?(aq)+C2H5OH(aq)
was measured at several temperatures, and the following data were collected:
Temperature (?C) k(M?1s?1) 15 0.0521 25 0.101 35 0.184 45 0.332
Problem 14.65 The rate of the reaction
CH3COOC2H5(aq)+OH?(aq)?CH3COO?(aq)+C2H5OH(aq)
was measured at several temperatures, and the following data were collected:
Temperature (?C) k(M?1s?1) 15 0.0521 25 0.101 35 0.184 45 0.332
The rate of the reaction
CH3COOC2H5(aq)+OH?(aq)?CH3COO?(aq)+C2H5OH(aq)
was measured at several temperatures, and the following data were collected:
Temperature (?C) k(M?1s?1) 15 0.0521 25 0.101 35 0.184 45 0.332
The rate of the reaction
CH3COOC2H5(aq)+OH?(aq)?CH3COO?(aq)+C2H5OH(aq)
was measured at several temperatures, and the following data were collected:
Temperature (?C) k(M?1s?1) 15 0.0521 25 0.101 35 0.184 45 0.332
Part A Using these data, graph lnk versus 1/T.

Part B Calculate the value of Ea by using your graph.






Part B Calculate the value of Ea by using your graph.



Temperature (?C) k(M?1s?1) 15 0.0521 25 0.101 35 0.184 45 0.332

Explanation / Answer

it is a 1st order reaction ln k Vs1/T graph can give straight line having intercept

by using log(K2/K1) =Ea/2.303R[1/T1 - 1/T2]

WE CAN CAL. Ea VALUE

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