IF anyone can help me with this involved question it would be greatly appreaciat
ID: 810288 • Letter: I
Question
IF anyone can help me with this involved question it would be greatly appreaciated.
the following data were collected from two separate experiments for the following reaction in aqueous, by measuring the number of moles of Hg2Cl2 that precipated per liter per minute
2HgCl2(aq) + C2O4^2-(aq) ---> 2Cl-(aq) + 2CO2(g) Hg2Cl2 (s)
Experiment 1 Experiment 2
time HgCl2 mol/L excess C2O4^2- C2O4^2- mol/L excess HgCl2
0 0.150 0.300
3.33 0.0843 0.283
5.00 0.0755 0.275
6.67 0.0676 0.268
8.33 0.0606 0.261
10.00 0.0543 0.254
16.67 0.0340 0.229
23.33 ? ?
b.) Write the integrated rate law and the rate constant (K') with respect to HgCl2 and the integrated rate law and rate constant (K'') with respect to C2O4^2-
Explanation / Answer
The concentration data must be multiplied by the time to obtain concentration at the given time. Then by plotting the concentration against time and fitting the data point with best fitting curves by regression method, one can obtain the integrated rate law and the slope (once the fitting curve equation is known the data can be plotted in such a way that it fits with a straight line) is the rate constant.
data in experiment 1 gives rate law and rate constant with respect to oxalate ion and that in experiment 2 gives rate law and rate constant with respect to HgCl2.