Please answer all the questions 5,6,7 show steps The phrase \"like dissolves lik

Question

Please answer all the questions 5,6,7 show steps

The phrase "like dissolves like" refers to the fact that When Solution of strong electrolytes in water are formed, the ions are surrounded by water molecules. These interactions are described as a case of A saturated solution Which one of the following substances would be the most soluble in CCI4? Calculate the molality of a 25.4% (by mass) aqueous solution of phosphoric acid (H3PO4). Calculate the molarity of a 25.4% (by mass) aqueous solution of phosphoric acid (H3PO4). The density of the solution is 1.25 g/mL. Calculate the mole fraction of phosphoric acid (H3PO4) in a 25'.4% (by mass) aqueous solution.

Explanation / Answer

5. moles of H3PO4 = 25.4 g x 1 mol/98 g = 0.259 mol H3PO4

Kg of solvent = (100g - 25.4 g) = 74.6 g = 0.0746 kg

Molality = moles of solute/kg of solvent = 0.259 mol/0.0746 kg solvent

Molality = 3.47m

6. Molarity = moles of solute / liter of solution ( M = n / V)
Molality = moles of solute / kg of solvent ( m = n / kg)
Density = mass of solution / volume of solution ( d = mass/V)

moles of H3PO4 = 25.4 g x 1 mol/98 g = 0.259 mol H3PO4

Weight of solution = 100g

Density = 1.25g/ml

Therefore, Volume of solution = Weight of Sol * density = 125ml

Therefore, molarity = (0.259mol/125ml) * 1000ml =2.07 M

7. moles of H3PO4 = 25.4 g x 1 mol/98 g = 0.259 mol H3PO4

moles of water = (100-25.4)x1mol/18g =4.144mol water

Therefore, mole fraction of H3PO4 in aqueous solution = 0.259/(0.259+4.144) = 0.0589

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