Please explain how you solved! Thanks! The atomic masses of nitrogen-14, titaniu
ID: 871733 • Letter: P
Question
Please explain how you solved! Thanks!
The atomic masses of nitrogen-14, titanium-48, and xenon- 129 are 13.999234 amu, 47.935878 amu, and 128.904779 amu, respectively.
A) For each isotope, calculate the nuclear mass.
Express your answers using six decimal places separated by commas. m14N, m48Ti, m129Xe =
B) For 14N, calculate the nuclear binding energy.
Express your answer using six significant figures.
C) For 48Ti, calculate the nuclear binding energy.
Express your answer using six significant figures.
D) For 129Xe, calculate the nuclear binding energy.
Express your answer using seven significant figures.
E) For 14N, calculate the nuclear binding energy per nucleon.
Express your answer using six significant figures.
F) For 48Ti, calculate the nuclear binding energy per nucleon.
Express your answer using six significant figures.
G) For 129Xe, calculate the nuclear binding energy per nucleon.
Express your answer using seven significant figures.
Explanation / Answer
Nitrogen-14 has 7 protons and 7 neutrons. The combined mass of the subatomic particles is
7 * (proton mass) + 7 * (neutron mass)
7 * (1.00728 amu) + 7 * (1.00866 amu ) = 14.11158 amu
The reported mass of Nitrogen is 13.998947 amu, so the mass defect (difference) is 14.11158 amu - 13.998947 amu = 0.112633 amu