Part A In Europe, gasoline efficiency is measured in km/L. If your car\'s gas mi
ID: 877016 • Letter: P
Question
Part A
In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 28.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe? Use the following conversions: 1km=0.6214mi and 1gal=3.78L.
Express your answer numerically in liters.
Part B
While in Europe, if you drive 125 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 42.0 mi/gal ? Assume that 1euro=1.26dollars.
Express your answer numerically in dollars.
Part C
A sprinter set a high school record in track and field, running 200.0 m in 21.0 s . What is the average speed of the sprinter in kilometers per hour?
Express your answer numerically in kilometers per hour.
Part D
A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece. How many kilograms of dietary fat are in a box containing 4.00 lb of candy?
Express your answer numerically in kilograms.
Explanation / Answer
part A )
1km = 0.6214mi
1 mi = 1/0.621
= 1.61 Km
28.0 mi/gal = 28 x 1.61 / 3.78
= 11.93 Km / L
for 1 litre -----------------> 11.93 Km mileage
howmany litres (x)----------------> 142 Km
x = 142 / 11.93
x = 11.90L
11.90 L gasoline required to travel 142 Km
part B )
42 mi / gal = 42 x 1.61 / 3.78
= 17.89 Km / L
car mileage = 17. 89 Km / L
for 1 day car travels = 125 Km
1 week car travels = 125 x 7 = 875 km
car mileage per litre = 17. 89 Km
? = 875 km
x = 875 / 17.89
= 48.91 L
for 1 week 48.91 L gasoline is required to travel 875 km
for litre cost of gasoline = 1.10 euros
48.91 litre gasoline cost = 48.91 x 1.10
= 53.80 euros
1 euro = 1.26 dollars
53.80 euros = 1.26 x 53.80
= 67.79 dollars
for one week 67.79 dollars of money he can spend
part C )
speed = distance / time
= 200 / 21
= 9.524 m/s
1 kmph = 5/18 m/s
1 m/s = 18/5 kmph
9.524 m/s = 9.524 x 18/5
= 34.27 kmph
speed of the sprinter 34.27 kilometers per hour
part D )
22.7 g piece contain fat = 7 g
1 lb = 453.592 g
4 lb candy = 4 x 453.592
= 1814.368g
22.7 g piece contain fat = 7 g
? =1814.368g
fat = 22.7 x 1814.368 / 7
= 5883.73 g
= 5.88 Kg
dietary fat = 5.88 Kg