Part A In Europe, gasoline efficiency is measured in km/L. If your car\'s gas mi
ID: 983553 • Letter: P
Question
Part A
In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 28.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe? Use the following conversions: 1km=0.6214mi and 1gal=3.78L.
Express your answer numerically in liters.
Part B
While in Europe, if you drive 123 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 28.0 mi/gal ? Assume that 1euro=1.26dollars.
Express your answer numerically in dollars.
Part C
A sprinter set a high school record in track and field, running 200.0 m in 20.9 s . What is the average speed of the sprinter in kilometers per hour?
Express your answer numerically in kilometers per hour.
Part D
A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece. How many kilograms of dietary fat are in a box containing 2.00 lb of candy?
Express your answer numerically in kilograms.
Explanation / Answer
Part A
In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 28.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe? Use the following conversions: 1km=0.6214mi and 1gal=3.78L.
Rate = 28 mi / gal
28 mi = 1609.34*28 = 45061.52 m
then gal = 3.78 L
Rate = 45061.52 m / gal * 1gal / 3.78 L = 11921.037037 m/L = 1.19 km/L
Rate = D/V
Total distance = 142/1.19 = 119.327731092 L will be needed
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