Individuals with genotype RrSS will produce how many different kinds of gametes?
ID: 88256 • Letter: I
Question
Individuals with genotype RrSS will produce how many different kinds of gametes?
what are the possible gameste combinations if parent is AaBb?
white eyes in fruit flies are a sex linked recessive trait. a cross between a homozygous red eyed female and white eyed male should produce what phenotypes?
if a rose, homozygous for tall and red (tall and red are dominant) were crossed witha short and white rose.. what would be phenotype of F1 generation?...what would be genotype of F1 generation?.. what would be genotype of the rose that is homozygous tall and red?
what is characteristic phenotypic ratio of a dihybrid punnet square when you cross two heterozygote individuals?
what is the only possible gamete combination if parent is AaBBCc?
what is phenotypic ratio of a monohybrid punnet square b/w two heterozygous individuals?
what is the chance that woman would have cystic fibrosis if one of her parents was a heterozygous for disorder and the other is homozygous dominant? cystic fibrosis is homozygous recessive.
in cattle, red color is codominant to white. the hybrid is roan (reddish brown).. what is expected gentoype of cross of two roan cattle?
plz show all work.
Explanation / Answer
Question: Individuals with genotype RrSS will produce how many different kinds of gametes?
Answer: The individual in question RrSS will produce 2 different types of gametes with alleles are RS and rS in equal ratio.
Question: What are the possible gametes combinations if parent is AaBb?
Answer: The individual in question will produce four gametes as AB, aB, Ab and ab in 1:1:1:1 ratio.
Question: White eyes in fruit flies are a sex linked recessive trait. a cross between a homozygous red eyed female and white eyed male should produce what phenotypes?
Answer: Taking homozygous red eyed female (XX) and homozygous white eyed male (YY) as the fruit fly eye character is sex linked it will be present on X chromosome. Now let’s see below the cross between gametes:
Gametes
X
X
X
XX
XX
Y
XY
XY
The cross explains that two offspring’s will receive sex linked recessive gene (one female and one male) in the ratio 1:1. But phenotypically only recessive male will have red eyed, One male will have white eye and Both the females will have white eyes but one female will carry the gene for further inheritance.
Question: what is characteristic phenotypic ratio of a dihybrid punnet square when you cross two heterozygote individuals?
Answer: In dihybrid punnet square, two traits are being crossed when both the parents are heterozygous. The phenotype ratio predicted for dihybrid cross is 9:3:3:1. Of the sixteen possible allele. Below explained with punnet square
Gametes
AB
Ab
aB
ab
AB
AABB
AABb
AaBB
AaBb
Ab
AABb
Aabb
AaBb
Aabb
aB
AABb
AaBb
aaBB
aaBb
ab
AaBb
Aabb
aaBb
aabb
9 gametes will have dominant allele from both the parents
3 gametes will have dominant gene from single parents
1 gamete will get both the recessive allele.
Question : what is the only possible gamete combination if parent is AaBBCc?
Answer: This can be solved by formula as to 2^n where n represent number of heterozygous position of gene. If a parent is having AaBBCc, contain 2 heterozygous position of genes so to 2^2 = 4 four different gametes produced will be ABC, ABc, aBC, aBc.
Question: what is phenotypic ratio of a monohybrid punnet square b/w two heterozygous individuals?
Answer: To understand this condition check below punnet square taking two heterozygous individuals as Aa and Bb:
Gametes
A
a
B
AB
aB
b
Ab
aa
The above cross explains there will be production of four individuals with different gametes in ration (1:1:1:1) one individual will be purely dominant one will be purely recessive and two individual will recessive one dominant gene from different parents.
Question: What is the chance that woman would have cystic fibrosis if one of her parents was a heterozygous for disorder and the other is homozygous dominant? cystic fibrosis is homozygous recessive.
Answer: As cyctic fibrosis is caused by recessive allele, and express itself when a person individual receives both the recessive allele for disease. In the question one parent is homozygous recessive (mother XX: both the X chromosome have disease allele) and one is heterozygous (father XY here X is having disease allele). So after crossing XX and XY with disease alleles all the females will be homozygous dominant.
Gametes
X
X
X
X X
X X
Y
XY
X Y
The cross explains that two offspring’s will receive sex linked recessive gene ( one female and one male) in the ratio 1:1. But phenotypically only recessive male will have red eyed, One male will have white eye and Both the females will have white eyes but one female will carry the gene for further inheritance.
Question: In cattle, red color is codominant to white. The hybrid is roan (reddish brown).What is expected genotype of cross of two roan cattle? plz show all work.
Answer: Taking red colour is dominant as ( RR) and white as recessive ( rr), now combination will produce Rr individual which is Roan. Now crossing 2 roan cattle
Gametes
R
r
R
RR
Rr
r
Rr
rr
The genotype is 3:1 and three offsprings will be Roan and one will be white
Gametes
X
X
X
XX
XX
Y
XY
XY
The cross explains that two offspring’s will receive sex linked recessive gene (one female and one male) in the ratio 1:1. But phenotypically only recessive male will have red eyed, One male will have white eye and Both the females will have white eyes but one female will carry the gene for further inheritance.