Consider the following reaction in which HCl adds across the double bond of etha
ID: 914878 • Letter: C
Question
Consider the following reaction in which HCl adds across the double bond of ethane:
HCl+H2C=CH2H3CCHCl
The following mechanism, with the energy diagram shown below, has been suggested for this reaction:
Step 1 HCl+H2C=CH2H3C=CH+2+Cl
Step 2 H3C=CH+2+ClH3C=CH2Cl
Part A
Based on the energy diagram (Figure 1) , which step is rate limting?
Part B
What is the expected order of the reaction based on the proposed mechanism?
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Part C
Is the overall reaction exothermic or endothermic?
Figure 1 of 1
Consider the following reaction in which HCl adds across the double bond of ethane:
HCl+H2C=CH2H3CCHCl
The following mechanism, with the energy diagram shown below, has been suggested for this reaction:
Step 1 HCl+H2C=CH2H3C=CH+2+Cl
Step 2 H3C=CH+2+ClH3C=CH2Cl
Part A
Based on the energy diagram (Figure 1) , which step is rate limting?
a) the first step b) the second stepPart B
What is the expected order of the reaction based on the proposed mechanism?
a) zero order b) first order c) second orderSubmitMy AnswersGive Up
Part C
Is the overall reaction exothermic or endothermic?
a) exothermic b) endothermicFigure 1 of 1
Explanation / Answer
1) Slowest step is rate llimiting step.
Therefore, Answer = a ( first step)
2) Two reactants are involved in rate limiting step.
Therefore, it is 2nd order reaction.
Hence, answer = c
3) Since heat energy is released, it is exothermic reaction.
Hence, answer= a