Problem 16.35 Complete the following table by calculating the missing entries an

Question

Problem 16.35

Complete the following table by calculating the missing entries and indicating whether the solution is acidic or basic.

Part A

Complete the first row.

Express your answer using two significant figures.

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Part B

Complete the first row.

Express your answer using two decimal places.

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Part C

Complete the first row.

Express your answer using two decimal places.

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Part D

Complete the first row. Indicate whether the solution is acidic or basic.

Complete the first row. Indicate whether the solution is acidic or basic.

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Part E

Complete the second row.

Express your answer using two significant figures.

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Part F

Complete the second row.

Express your answer using two decimal places.

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Part G

Complete the second row.

Express your answer using two decimal places.

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Part H

Complete the second row. Indicate whether the solution is acidic or basic.

Complete the second row. Indicate whether the solution is acidic or basic.

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Part I

Complete the third row.

Express your answer using two significant figures.

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Part J

Complete the third row.

Express your answer using two significant figures.

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Part K

Complete the third row.

Express your answer using two decimal places.

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Part L

Complete the third row. Indicate whether the solution is acidic or basic.

Complete the third row. Indicate whether the solution is acidic or basic.

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Part M

Complete the fourth row.

Express your answer using two significant figures.

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Part N

Complete the fourth row.

Express your answer using two significant figures.

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Part O

Complete the fourth row.

Express your answer using two decimal places.

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Part P

Complete the fourth row. Indicate whether the solution is acidic or basic.

Complete the fourth row. Indicate whether the solution is acidic or basic.

[H+] [OH] pH pOH Acidic or basic? 7.6×103M 3.6×1010M 8.28 5.72

Explanation / Answer

Part B: pH = -logc =  -log[7.6 x 10-3] = 2.1

Part D: Acidic

Part G : pOH = -log[OH-] =  -log[3.6 x 10-10 ] = 9.4

Part H : Basic

Part I : [H+] = antilog(-pH) = antilog(-8.28) = 5.2 x 10-9

Part L : Basic

Part N: [OH-] = antilog(-pOH) = antilog(-5.72) = 1.9 x 10-6

Part P: Basic

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