Commercial vinegar and sodium hydroxide with methyl red indicator Mass of analyt

Question

Commercial vinegar and sodium hydroxide with methyl red indicator Mass of analyte. Volume of analyte Volume of titrant Commercial vinegar and sodium hydroxide with phenolphthalein indicator Mass of analyte. Volume of analyte Volume of titrant. Titration #3: Hydrochloric acid and sodium hydroxide with methyl red indicator Mass of analyte Volume of analyte Volume of titrant Titration #4: Hydrochloric acid and sodium hydroxide with phenolphthalein indicator Mass of analyte Volume of analyte Volume of titrant.

Explanation / Answer

1.
Molar mass of vinegar = 60.05 g/mol
m = 1.963 g
number of moles = mass / molar mass
                                   = 1.963 / 60.05
                                   =0.0327 mol
v = 2 mL = 0.002 L

concentration = number of moles / volume
                              = 0.0327/0.002
                              =16.34 M

2.

Molar mass of vinegar = 60.05 g/mol
m = 1.98 g
number of moles = mass / molar mass
                                   = 1.98 / 60.05
                                   =0.033 mol
v = 2 mL = 0.002 L

concentration = number of moles / volume
                              = 0.033/0.002
                              =16.49 M

3.
Molar mass of HCl = 36.46 g/ml
m = 9.952 g
number of moles = mass / molar mass
                                   = 9.952 / 36.46
                                   =0.273 mol
v = 10 mL = 0.01 L

concentration = number of moles / volume
                              = 0.273/0.01
                              =27.3 M

4.
Molar mass of HCl = 36.46 g/ml
m = 9.934 g
number of moles = mass / molar mass
                                   = 9.934 / 36.46
                                   =0.272 mol
v = 10 mL = 0.01 L

concentration = number of moles / volume
                              = 0.272/0.01
                              =27.2 M

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