Consider the reaction: 2COF_2(g) doubleheadarrow CO_2(g) + CF_4(g) Calculate K_c
ID: 960230 • Letter: C
Question
Consider the reaction: 2COF_2(g) doubleheadarrow CO_2(g) + CF_4(g) Calculate K_c for the following reaction: 2CO_2(g) + 2CF_4(g) doubleheadarrow 4COF_2(g) Question 4: At 100degreeC the equilibrium constant for the reaction COCl_2 doubleheadarrow CO(g) + Cl_2(g) has the value of K_c = 2.19^8 10^-19. With the following amounts added:[COCl_2] = 3.50*10^-3 M. [CO] = 1.11*10^-5 M, [Cl_2] = 3.25* 10^-6, what is the value of the reaction quotient? Question 5: Which direction (if any) does the above reaction (Question 4) need to proceed to reach equilibrium?Explanation / Answer
2COF2(g) <-----> CO2 + CF2(g)
K = {PCO2*PCF2}/{PCOF2}2= 2.2*106
For the reaction :- 2CO2(g) + 2CF2(g) <----> 4COF2(g) ; K = {PCOF2}4/{PCO2*PCF2}2 = 1/(2.2*106)2 = 2.066*10-13
2) COCl2(g) <----> CO(g) + Cl2(g)
Reaction quotient = {[CO]*[Cl2]}/[COCl2] = 1.031*10-7
Since reaction quotient > Equilibrium constant, the reaction will move in the backward direction, i.e formation of COCl2 will occur.