For the next two questions consider the following Lewis Structure The nitrogen/n

Question

For the next two questions consider the following Lewis Structure The nitrogen/nitrogen double bond includes a sigma bond made from the overlap of... hybridized sp orbitals from both nitrogens hybridized sp^2 orbitals from both nitrogens hybridized sp^3 orbitals from both nitrogens atomic s orbitals from both nitrogens atomic p orbitals from both nitrogens The nitrogen/nitrogen double bond includes a pi bond made from the overlap of... hybridized sp orbitals from both nitrogens hybridized sp^2 orbitals from both nitrogens hybridized sp^3 orbitals from both nitrogens atomic s orbitals from both nitrogens atomic p orbitals from both nitrogens Consider the polyatomic ions NO_2^+, NO_2^- and NO_3^-. Which has the largest bond order, NO_2^+ has the highest bond order and NO_3^- has the lowest bond order NO_2^- has the highest bond order and NO_2^+ has the lowest bond order NO_3^- has the highest bond order and NO_2^- has the lowest bond order

Explanation / Answer

In the given molecule each nitrogen has two sigma bonds, a pi bond and one lone pair. Two sigma bonds and a lone pairs needs hybrid orbitals, so each nitrogen undergoes sp2 hybridization to produce three sp2 hybrd orbitals, among the three hybrid orbitals two can be used to form two sigma bonds (one with H atom and another one with adjacent nitrogen atom) and third sp2 hybrid orbital holds lone pair of electrons.

After formation of two sigma bonds each nitrogen has an unhybridized p orbital with an unpaired electron. This unhybridized p orbital overlap laterally with another unhybridized p orbital on another N atom to form pi bond.

14 answer : b) hybridized sp2 orbitals from both nitrogens.

15. Answer : e) atomic p-orbitals from both nitrogens.

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