Can someone explain to me how this is the correct answer. Please show all work.

Question

Can someone explain to me how this is the correct answer. Please show all work.

Cocaine is a chiral compound and, therefore, could exist as a pair of enantiomers. The levorotatory isomer occurs naturally and is physiologically active, whereas the dextrorotatory isomer does not occur naturally and is physiologically inactive. Pure natural cocaine has an [ab25 of-16. The cocaine Rusty, the friendly neighborhood drug dealer, sells, which he swears to be of the finest quality, has a [ab25 of +8 . What is the percent composition of the physiologically active enantiomer in the cocaine Rusty sells, assuming that it is mixture of the two enantiomers of cocaine? 25% 50% 67% 75% none of the above

Explanation / Answer

active cocine = x

fraction of inactive cocaine = 1 - x

hence

-16 x + 16 (1-x) = +8

-16 x + 16 -16 x = 8

32 x = 8

x = 8/ 32

x = 1/4 fraction

so

active cocain = 1/4 % = 25 %

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---