Problem 15: A student m1 = 66 kg stands on a long cart m2 = 122 kg initially at

Question

Problem 15: A student m1 = 66 kg stands on a long cart m2 = 122 kg initially at rest. He begins to run in the cart with a speed relative to the ground of v1 = 3.1 m/s.

Part (a) Write an expression for the carts velocity relative to the ground while the student is running. Assume the student is running in the positive x-direction.

Part (b) What is the velocity in meters per second?

Part (c) What is the students velocity relative to the cart in meters per second? Use a coordinate system fixed to the cart which has the same orientation for the x-axis as the system fixed to the ground we defined in part (a). Comment

Explanation / Answer

momentum of the system is conserved

M1v1 =- M2v2

v 2= 60*3.1/122 = 1.542m/s in negative x axis

relative velocity

as both are moving in opposite direction relative velocity is the sum of two velocities

R.V = 1.542+3.1 = 4.642m/s

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