For the capacitor network shown in the figure below( Figure 1 ) , the potential

Question

For the capacitor network shown in the figure below(Figure 1) , the potential difference across ab is 300V .

Part A

Find the total charge stored in this network.

Express your answer using two significant figures.

Part B

Find the charge on each capacitor.

Express your answers using two significant figures separated by a comma.

Part C

Find the total energy stored in the network.

Express your answer using two significant figures.

Part D

Find the energy stored in each capacitor.

Express your answers using two significant figures separated by a comma.

Part E

Find the potential difference across each capacitor.

Express your answers using two significant figures separated by a comma.

Explanation / Answer

Ceq = (35+75)nF = 110nF

A) Qtotal = Ceq * V = 110 x 300 nC = 33000nC = 33uC

B) Q35 = C35*V = 35n*300 = 10500nC = 10.5uC

Q75 = c75*V = 75n*300 = 22.5uC

C) total energy (U)= 1/2 * Ceq * V^2 = 0.5*110n * 300*300 = 4.95mJ

D) U35 = 1/2 * C35 * V^2 = 0.5*35n*300*300 = 1.575mJ

  U35 = 1/2 * C75 * V^2 = 0.5*75n*300*300 = 3.375mJ

E) V35 = 300V

V75 = 300V

Since both capacitors are in parallel, potential difference across them will remian same

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects