For the capacitor network shown in the figure below(Figure 1) , the potential di
ID: 2286117 • Letter: F
Question
For the capacitor network shown in the figure below(Figure 1) , the potential difference across ab is 46V . (There is 150 Nf on the left, 120 Nf on the right).
Find the total charge stored in this network.
Express your answer using two significant figures.
Find the charge on each capacitor.
Express your answers using two significant figures separated by a comma.
Find the total energy stored in the network.
Express your answer using two significant figures.
Find the energy stored in each capacitor.
Express your answers using two significant figures separated by a comma.
Find the potential difference across each capacitor.
Express your answers using two significant figures separated by a comma.
Find the total energy stored in the network.
Express your answer using two significant figures.
Find the energy stored in each capacitor.
Express your answers using two significant figures separated by a comma.
Find the potential difference across each capacitor.
Express your answers using two significant figures separated by a comma.
Explanation / Answer
equivalent Capaitance
1/Cab=1/150+1/120
Cab=66.67 nF
a)
Total Charge
Q=CabV=46*(66.67*10-9)
Q=3.07*10-6 or 3.07 uC
b)
Charge on each capacitor
Q150=Q=3.07*10-6 or 3.07 uC
Q120=Q=3.07*10-6 or 3.07 uC
c)
Energy stored in each capacitor
E=(1/2)(Q2/C)
E150=(1/2)(3.07*10-6)2/(150*10-9)=3.1*10-5 J or 31 uJ
E120=(1/2)(3.07*10-6)2/(120*10-9)=3.9*10-5 J or 39 uJ
d)
Voltage across each capacitor is
V=Q/C
V150=3.07*10-6/(150*10-9)=20.4 Volts
V120=3.07*10-6/(120*10-9)=25.6 Volts